Question

hey friends......

please help me
apko jitna atta h utna sol kero
but i need correct ans

Answer 1

1- 1
 8x2- 22x - 21 = 0

⇒ 8x2- 28x + 6x - 21 = 0

⇒ 4x(2x - 7) + 3(2x - 7) = 0

⇒ (2x - 7)(4x + 3) = 0

⇒ (2x - 7) = 0 or (4x + 3) = 0

⇒   x = 7/2 or x = -3/4

1- 2

Solve Using the Quadratic Formula 9x^2-3x-2=0

9x2−3x−2=09x2-3x-2=0

Use the quadratic formula to find the solutions.

−b±√b2−4(ac)2a-b±b2-4(ac)2a

Substitute the values a=9a=9, b=−3b=-3, and c=−2c=-2 into the quadratic formula and solve for xx.

3±√(−3)2−4⋅(9⋅−2)2⋅93±(-3)2-4⋅(9⋅-2)2⋅9

Simplify.

Tap for more steps...

x=1±36x=1±36

The final answer is the combination of both solutions.

x=23,−13

1- 3

3x2 + 10x + 7√3 = 0

√3x2 + 7x + 3x + 7√3 = 0

x ( √3x + 7 ) + √3 ( √3x + 7 ) =  0

(x + √3) ( √3x + 7) = 0

x + √3 = 0       ,        √3x +7 = 0

x= -√3                       x= -7/ √3

So, the 2 zeroes are -√3 and -7/√3

Sum of zeroes =  -√3 + (-7/√3)

                           = -√3 - 7/√3

                           = -10/ √3 = -b/a 

Product of zeroes = -√3 * - 7/√3

                                 = 7 = c/a

2-. 2

y = 3(x^2 + 11x/3) - 20/3 = 0
(x^2 + 11x/3 + 121/36) - 121/36 = 20/3
(x + 11/6)^2 = 20/3 + 121/36 = 361/36
(x + 11/6)^2 = 361/36 =
(x+116)=±196

x=−116+196=86=43

x=−116−196=−306=−5

2- 3

2x2−7x+3=0

⇒2(x2−72x)+3=0

⇒2(x2−2×74x+4916)=498−3=258

(x−74)2=2516⇒x−74=±54

⇒x=74±54=3