Hey Friends !!!
PLEASE SOLVE
CH- TRIGONOMETRY
CLASS - X
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3
by expanding L. H. S we get
sec^4¤-sec^2¤
= sec^2¤(sec^2¤-1)
= (1+tan^2¤)(1+tan^2¤ -1)
{as sec^2¤ = 1+tan^2¤}
= (1+tan^2¤)tan^2¤
= tan^4¤ + tan^2¤
= R. H. S
hence, proved
sec^4¤-sec^2¤
= sec^2¤(sec^2¤-1)
= (1+tan^2¤)(1+tan^2¤ -1)
{as sec^2¤ = 1+tan^2¤}
= (1+tan^2¤)tan^2¤
= tan^4¤ + tan^2¤
= R. H. S
hence, proved
Anonymous:
thank you so much
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Hi
Ur intro plz
vedha
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5
please mark it as brainliest
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thank you so much
wlcm
could u help me in other trigo questions also ??
yahh
so i m asking, please try to answer
sorry i had lost the internet connection
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