hey friends
pls help me with my question
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17
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⭐⭐⭐⭐⭐ ANSWER ⭐⭐⭐⭐⭐
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*⃣ INITIAL CONDITIONS *⃣
V1 = V cm³ (say)
T1 = 273 K
*⃣ FINAL CONDITIONS *⃣
V2 = 2V cm³
T2 =?
*⃣ From Charles' Law, *⃣
V1/T1 = V2/T2 (At constant pressure)
=> V/273 = 2V/T2
=> T2 = 546 K
=> T2 = (546-283)°C = 273°C
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⭐⭐⭐ ALWAYS BE BRAINLY ⭐⭐⭐
==================================
⭐⭐⭐⭐⭐ ANSWER ⭐⭐⭐⭐⭐
==================================
*⃣ INITIAL CONDITIONS *⃣
V1 = V cm³ (say)
T1 = 273 K
*⃣ FINAL CONDITIONS *⃣
V2 = 2V cm³
T2 =?
*⃣ From Charles' Law, *⃣
V1/T1 = V2/T2 (At constant pressure)
=> V/273 = 2V/T2
=> T2 = 546 K
=> T2 = (546-283)°C = 273°C
==================================
⭐⭐⭐ ALWAYS BE BRAINLY ⭐⭐⭐
==================================
Anonymous:
U r most welcome ^_^
Answered by
0
❤ HERE IS YOUR SOLUTION ❤
INITIAL CONDITIONS :-
V1 = V cm³ (say)
T1 = 273 K
FINAL CONDITIONS :-
V2 = 2V cm³
T2 =?
Now, we can apply Charles' Law,
V1/T1 = V2/T2 (At constant pressure)
=> V/273 = 2V/T2
=> T2 = 546 K
=> T2 = (546-283)°C = 273°C
Thus, ur answer is 273°C
INITIAL CONDITIONS :-
V1 = V cm³ (say)
T1 = 273 K
FINAL CONDITIONS :-
V2 = 2V cm³
T2 =?
Now, we can apply Charles' Law,
V1/T1 = V2/T2 (At constant pressure)
=> V/273 = 2V/T2
=> T2 = 546 K
=> T2 = (546-283)°C = 273°C
Thus, ur answer is 273°C
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