Question

hey friends plz solve this question with explanation..... plz... ​

Answer 1

Answer:

m₁ = mass of first ball = 4 kg

v₁ = velocity of first ball before collision = v

v'₁ = velocity of first ball after collision = v/4

m₂ = mass of second ball = m

v₂ = velocity of second ball before collision = 0

v'₂ = velocity of second ball after collision = ?

using conservation of momentum

m₁ v₁ + m₂ v₂ = m₁ v'₁ + m₂ v'₂

inserting the above values

4 v + m (0) = 4 (v/4) + m v'₂

m v'₂ = 3 v                                    

v'₂ = 3v/m                              eq-1

using conservation of kinetic energy for the elastic collision

m₁ v²₁ + m₂ v²₂ = m₁ v²'₁ + m₂ v²'₂

4 v² + m (0)² = 4 (v/4)² + m v²'₂

4 v² = (0.25) v² + m v²'₂

(3.75) v² = m v²'₂

using eq-1

(3.75) v² = m (3v/m)²

(3.75) v² = m (9 v²)/m²

(3.75) = (9)/m

m = 9/3.75

m = 2.4 kg

so the correct choice is "C"

Answer 2

Answer:

mass = 2.4kg

please inbox me

it's a request