Question

❇❇HEY FRIENDS!! ✨✨
QUESTION....
✨✨
A STUDENT WALKS FROM HIS HOUSE AT 5KM/HR❇ AND REACHES HIS SCHOOL 10 MINUTES LATE. ✨IF HIS SPEED❇ HAD BEEN 6KM/HR , HE WOULD HAVE REACHED 15 MINUTES EARLY. ✨✨THE DISTANCE OF HIS SCHOOL FROM HIS HOUSE IS.....

EXPLANATION + GOOD ANSWER NEEDED✔✔⬅⬅

Answer 1

Answer:

Hence, the distance between school and his house is 12.5 km

Step-by-step explanation:

Hi,

Let the distance between school and home be 'x' km.

Time taken to reach school if student walks at 5 kmph will be x/5 hr

Time taken to reach school if student walks at 6 kmph will be x/6 hr.

Given that (x/5 - x/6) hr = 25 min

Converting minutes into hours, we get

25 minutes = 25/60 hr = 5/12 th of hour

Hence x/5 - x/6  = 5/12

=> x/30 = 5/12

=> x = 25/2 or

x = 12.5 km.

Hence, the distance between school and his house is 12.5 km.

Hope, it helps !

Answer 2

Let us say that the actual distance between Ram's house and school is 'd' km and the ideal time to cover the distance is 't' hours.

When he walks at 5 kmph, he reaches 5 minutes (or 1/12 hours) early
=> d/5 = t - 1/12
=> t = d/5 + 1/12

When he walks at 4 kmph, he reaches 5 minutes (or 1/12 hours) late
=> d/4 = t + 1/12
=> t = d/4 - 1/12

Using the above equations, we can say 
d/5 + 1/12 = d/4 - 1/12
=> d/4 - d/5 = 1/12 + 1/12
=> d/20 = 1/6
=> d = 20/6 = 3.33 km
let thing the boy to ram