Question

HEY FRIENDS ...
SOLVE THE EQUATION AND ALSO VERIFY IT
please help me

Answer 1

$\underline{\large\bf{\mathfrak{Hello!}}}$

$= > \frac{4x - 3}{10x - 9} = \frac{0.05}{0.25} \\ \\ = > 0.25(4x - 3) = 0.05(10x - 9) \\ \\ = > 1x - 0.75 = 0.5x - 0.45 \\ \\ = > 1x - 0.5x = - 0.45 + 0.75 \\ \\ = > 0.5x = 0.3 \\ \\ = > x = \frac{0.3}{0.5} \\ \\ = > x = 0.6$

$\boxed{x = 0.6}$

$Verification \: of \: value \: of \: 'x'. \\ \\ LHS \\ = > \frac{4(0.6) - 3}{10(0.6) - 9} \\ \\ = > \frac{2.4 - 3}{6 - 9} \\ \\ = > \frac{ - 0.6}{ - 3} \\ \\ = > \frac{ 0.6 }{3 } \\ \\ = > 0.2 \\ \\ RHS\\ = > \frac{0.05}{0.25} \\ \\ = > 0.2 \\ \\ Therefore, \\ \\ LHS = RHS \\ \\ Hence, \: Verified!$

$<marquee> Hope this helps...:)$

Answer 2

Given,

$\frac{4x-3}{10x-9}=\frac{0.0.5}{0.25}\\\;\\\frac{4x-3}{10x-9}=\frac{0.5}{0.25}\times\frac{100}{100}\\\;\\\frac{4x-3}{10x-9}=\frac{5}{25}\\\;\\\frac{4x-3}{10x-9}=\frac{1}{5}\\\;\\5(4x-3)=10x-9\\\;\\20x-15=10x-9\\\;\\20x-10x=15-9\\\;\\10x=6\\\;\\x=\frac{6}{10}\\\;\\\textbf{x = 0.6}$

Verification:-

L.H.S.

$\frac{4x-3}{10x-9}\\\;\\=\frac{4\times0.6-3}{10\times0.6-9}\\\;\\=\frac{2.4-3}{6-9}\\\;\\=\frac{-0.6}{-3}\\\;\\=\frac{6}{30}\\\;\\=\frac{1}{5}$

R.H.S.

$\frac{0.05}{0.25}\\\;\\=\frac{5}{25}\\\;\\=\frac{1}{5}$

L.H.S. = R.H.S.