Question

Hey friendzz ^_____^❤❤.

plez answer this ques....☺.

✔convert a joule into arguments.

with full explanation.

Answer 1

Joule is SI unit of heat
1 Joule is the amount of energy on the mass of 1 kg
1 joule= 10ki power 7 erg

Answer 2

Hay!!

JQ of work is done in the MKS method whereas in the CGS system, the working quantity is ergonomed, hence the working

formula =>
$n(m1l1 {}^{ 2} t1 {}^{ - 2} ) \: = n2(m2l2 {}^{2} t2 {}^{ - 2} )$



$n2 = n1( \frac{m1}{m2} ) \: ( \frac{l1}{l2} ) {}^{2} ( \frac{t1}{t2} ) {}^{ - 2}$


n1 => 1 joule


$= 1( \frac{kg}{g} )( \frac{m}{cm} ) {}^{2} ( \frac{sec}{sec} ) {}^{ - 2}$

now we changed it in

$= 1( \frac{1000g}{g} )( \frac{100cm}{cm} ) {}^{2} (1) {}^{ - 2}$



$= 1000 \times 100 \times 100$


$= 10 {}^{7}$

1 Joule = 10^7 argument


I hope it's help you