Question

HEY FRND NEED HELP ............!!!!!

RUBBING alcohol was found to contain 60% carbon 13.4 percent hydrogen and the remaining mass due to oxygen . what is the empirical formula of rubbing alcohol???????

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Answer 1

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➡So rubbing alcohol contains 60 % carbon, 13.4 % hydrogen and 26.6 % oxygen, the difference. 

➡Now we have to convert % to atoms ( or mole) To do this we divide by the relative atomic mass. 

C = 60/12 = 5 

H = 13.4/1 = 13.4 

O = 26.6/16 = 1.66 

➡This is your empirical formula. However it doesn't really make sense having decimal points. 

So divide by 1.66 

C = 5/1.66 = 3.01 

H = 13.4/ 1.66 = 8.07 

O = 1.66/1.66 = 1 

➡This makes more sense. C3H8O, the empirical formula.

Answer 2

Answer:

The oxygen must be 100% - 60% - 13.4% = 26.6%

Imagine we have 100 g of rubbing alcohol. Now we can convert these percentages into grams. Then we can divide by their atomic mass to get moles.

C: 60 g / (12.0 g/mol) = 5 mol

H: 13.4 g / (1.0 g/mol) =13.4 mol

O: 26.6 g / (16.0 g/mol) = 1.6625

Divide each number by the smallest number, 1.6625. This gives us

C3H­8O.

Explanation:

I hope that this is right.

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