Hey frnd !!
need ur help!
A ion with mass no. 37 posses one unit of negative charge if the ion contain 11.1% more neutral than electron .find symbols of the ion ???
spam ans will be deleted on the spot .........☺☺☺
Answers
Answered by
1
Let the number of electrons in the ion carrying a negative charge be x.
Then,
Number of neutrons present
= x + 11.1% of x
= x + 0.111 x
= 1.111 x
Number of electrons in the neutral atom = (x – 1)
(When an ion carries a negative charge, it carries an extra electron)
∴ Number of protons in the neutral atom = x – 1
Therefore 37 = 1.111x + x -1
Or 2.111 x = 38
Or x = 18
Therefore no of protons = atomic no = x -1 = 18 – 1 = 17
37
the symbol is cl-
17
✌✌ hope you like my answer and it may help you ❤❤☺
Then,
Number of neutrons present
= x + 11.1% of x
= x + 0.111 x
= 1.111 x
Number of electrons in the neutral atom = (x – 1)
(When an ion carries a negative charge, it carries an extra electron)
∴ Number of protons in the neutral atom = x – 1
Therefore 37 = 1.111x + x -1
Or 2.111 x = 38
Or x = 18
Therefore no of protons = atomic no = x -1 = 18 – 1 = 17
37
the symbol is cl-
17
✌✌ hope you like my answer and it may help you ❤❤☺
Answered by
0
Am I am not sure of it
Similar questions
History,
7 months ago
English,
7 months ago
Math,
1 year ago
English,
1 year ago
India Languages,
1 year ago