Question

HEY FRND!! NEED UR HELP ☺☺<br /><br />Plzz do it fast guys .....

Answer 1

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1) Formal change on Cl=v-1/2S-L

OR Cl=7-1/2(8)-0=3

Formal change on the three oxygen atom which has an electron pair shared by chlorine is formal charge on 0=6-1/2(2)-6=-1

Formal change on the oxygen atom which has an electron pair shared by chlorine and another by the hydrogen is formal change on 

O=6-1/2(4)-0=-4

Formal change on the H=1-1/2(2)-0=0

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2) Formal Charge= No. Of valence electron - No. Of unpaired electron - 1/2 [ No. Of bonded electron]

= 6 -0 - 1/2 (12)

=6 - 6

=0

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Answer 2

Formal Charge = No of Valence Electron - No. of Unpaired Electron - 1/2[No. Of Bonded Electron]

HClO4 [Structure is attached] : 7 - 0 - 1/2[14]

= 7 - 7

= 0

2) HSO4- [Structure Is Attached] : 6 - 0 - 1/2[12]

= 6 - 6

= 0