Question

hey frnds give answer with full solution and method ​

Answer 1

Answer:

B)

in order to prove we have to find both maximum & minimum values

Answer 2

Answer:

☞ Given,

initial velocity of ball, u=0

Final velocity of ball, v=?

Distance through which the balls falls, s=20m

☞ Acceleration

a=10 \: ms −2a=10ms−2

Time of fall, t=?

☞ We know

v {}^{2} - u {}^{2} = 2asv

2

−u

2

=2as

v {}^{2} −0=2×10×20=400v

2

−0=2×10×20=400

v=20msv=20ms

☞ Now using v=u+at we have

20=0+10×t20=0+10×t

t=2st=2s