Hey frnds!!❤❤<br />Plz ansr this!!!<br /><br />Show the formation of Na2O by the transfer of electrons.
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Ans: Atomic number of Sodium (Na) – 11 Electronic configuration of Sodium – 1s2 2s2 2p6 3s1 It has one valence electron, it will lose one electron to get octet configuration Atomic number of Oxygen (O) – 8 Electronic configuration of Oxygen – 1s2 2s22p4 It is two electrons short of octet configuration, thus it will gain two electrons. During the bond formation between Sodium and Oxygen, two Sodium atoms loses one electron each to Oxygen atom.2 Na -2e- → 2Na+ O + 2e- → O-2 2Na+ + O-2 → Na2O.....
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Ans: Atomic number of Sodium (Na) – 11 Electronic configuration of Sodium – 1s2 2s2 2p6 3s1 It has one valence electron, it will lose one electron to get octet configuration Atomic number of Oxygen (O) – 8 Electronic configuration of Oxygen – 1s2 2s22p4 It is two electrons short of octet configuration, thus it will gain two electrons. During the bond formation between Sodium and Oxygen, two Sodium atoms loses one electron each to Oxygen atom.2 Na -2e- → 2Na+ O + 2e- → O-2 2Na+ + O-2 → Na2O.....
● by HARSHIT
●BeBrainly....
● mark it as BRAINLIEST
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