Question

hey frnds
please tell me this 5th one.

Answer 1

Hey dear here is your answer!!!!!

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Firstly, let's note down the things provided to us:-

Area of trapezium - 120 m²

Height - 12 m

Let one of the sides be x

So, the other side is x + 10.

Area of a parallelogram is $\frac{h(s1+s2)}{2}$ where s1 and s2 are parallel sides.

According to question:-

120 = 12 x $\frac{2x+10}{2}$

120 = 12 x ( x + 5)

Transposing:-

$\frac{120}{12}$ = x + 5

10 = x + 5

Shift the terms:-

x = 10 - 5

x = 5 m

So, x + 10 = 15m

Therefore, the parallel sides are 5m and 15m.

❣️⭐ Hope it helps you dear...⭐⭐❣️❣️

Answer 2

Let the smaller side be X then the the larger parallel side would be X+10.

Height is given 12 m, and the area is 120 m squared.

Area of a trapezium = 1/2*(sum of parallel sides) *(height) = 120 m squared

=> 1/2* (X+X+10)*12 = 120

1/2*(2X +10)*12 = 120

6*(2X+10) = 120

2X+10 = 20

2X = 10

X = 5 m

=> X + 10 = 15 m