Question

hey frnds plz help me...on monday my maths paper is their..help me solving this qestion. ..

Answer 1

P(x) = x^2 + 6x + 15

Discriminent = b^2 - 4ac

= (6)^2 - 4(1)(15)

= 36 - 60

= - 24

Discriminent is negative.

So, the given polynomial has no real zero.

Answer 2

D=b²-4ac
  =6²-4*1*15
  =36-60
  = -24

Since 'D' i.e. discriminant is less than 0 this quadratic equation has no real roots i.e. no zero.




HOPE IT HELPS!!!!