Question

Hey Frnds !!

Plzz solve my question...

Plzz solve this question on copy...

Thnx. •_•

Answer 1

$\frac{1}{ \sqrt{3} - \sqrt{2} - 1 } = \frac{1}{ \sqrt{3} - (\sqrt{2} + 1) } \times \frac{{ \sqrt{3} + \sqrt{2} + 1 } }{{ \sqrt{3} + \sqrt{2} + 1 } } \\ = \frac{ \sqrt{3} + \sqrt{2} + 1 }{ { \sqrt{3} }^{2} - {( \sqrt{2} + 1) }^{2} } \\ \frac{ \sqrt{3} + \sqrt{2} + 1 }{3 - 2 - 1 - 2 \sqrt{2} } \\ = \frac{ \sqrt{3} + \sqrt{2} + 1}{ - 2 \sqrt{2} } \times \frac{ \sqrt{2} }{ \sqrt{2} } \\ = \frac{ \sqrt{6} + 2 + \sqrt{2} }{ - 2 \times 2} \\ = \frac{ - 1}{4} (2 + \sqrt{6} + \sqrt{2} ) \\ = \frac{ -1 }{4} (2 + 2.449 + 1.414) \\ = \frac{ - 1}{4} \times 5.863 \\ = - 1.466$