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ii) 2x2+y2+8z2–22–√xy+42–√yz–8xz
Answer:
2x2+y2+8z2–22–√xy+42–√yz–8xz
=(−2–√x)2+(y)2+(22–√z)2+(2×−2–√x×y)+(2×y×22–√z)+(2×22–√z×−2–√x)=(−2–√x+y+22–√z)2=(−2–√x+y+22–√z)(−2–√x+y+22–√z)..
hope it helps uh..
Answer:
2x2+y2+8z2–22–√xy+42–√yz–8xz
=(−2–√x)2+(y)2+(22–√z)2+(2×−2–√x×y)+(2×y×22–√z)+(2×22–√z×−2–√x)=(−2–√x+y+22–√z)2=(−2–√x+y+22–√z)(−2–√x+y+22–√z)..
hope it helps uh..
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