Question

hey GM guys plz help me out.......​

Answer 1

Solution :

⏭ Given:

✏ Two particles of equal mass go around a circle of radius R under the action of their mutual gravitation attraction.

⏭ To Find:

✏ Speed of each particle.

⏭ Concept:

✏ This question is completely based on force equilibrium.

✏ Here, two type of forces are acted on each particle.

1. Gravitational Force
2. Centrifugal Force

✏ For equilibrium condition

Gravitational Force = Centrifugal Force

⏭ Calculation:

$\mapsto \sf \: \frac{G {m}^{2} }{4 {R}^{2} } = \frac{m {v}^{2} }{R} \\ \\ \mapsto \sf \: \frac{Gm}{4R} = {v}^{2} \\ \\ \mapsto \sf \: \boxed{ \sf{ \orange{v = \frac{1}{2} \sqrt{ \frac{Gm}{R}}}} } \red{ \bigstar}$