Hey guy plzzzzzz! help me to solve this question.
How many zero are in product of 1×2×3×4×5×...........................1000
please answer it fast
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Answered by
0
Answer:
120 is your answer kal ka bhai
Answered by
1
According to arithmetic progressions,
a=1
d=a2-a1
d=2-1
d=1
n=1000
an=1000
S1000=1000/2(1 + 1000)
=500(1001)
=500500
Therefore, sum of first 1000 numbers is 500500
a=1
d=a2-a1
d=2-1
d=1
n=1000
an=1000
S1000=1000/2(1 + 1000)
=500(1001)
=500500
Therefore, sum of first 1000 numbers is 500500
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