Question

Hey guys!

A certain sum of money is deposited per month in recurring deposit account for 2 years. the maturity amount is rs. 132500 and rate of interest is 10% find the sum deposited per month. ​

Answer 1

Heya!!

Here's your answer!!

Let the sum deposited per month = ₹ P

T = 24 month

Total amount deposited = P × 24

$\bold{</em></strong><strong><em>(</em></strong><strong><em>I</em></strong><strong><em> </em></strong><strong><em>\: = \frac{p \times n(n + 1)}{2} \times \frac{</em></strong><strong><em>RT</em></strong><strong><em>}{100} </em></strong><strong><em>)</em></strong><strong><em>} \:$

therefore, P × 24(25)/2 × 10/100 × 1/12 = 5P/2

therefore, Amount deposited + 1 = Maturity amount

24 P + 5P/2 = 132500

therefore,

53P/2 = 132500

therefore,

₹5000

Glad help you,

it helps you,

thanks.

Answer 2

therefore, P × 24(25)/2 × 10/100 × 1/12 = 5P/2

therefore, Amount deposited + 1 = Maturity amount

24 P + 5P/2 = 132500

therefore,

53P/2 = 132500

therefore,

₹5000

Glad help you,

it helps you,

thanks.therefore, P × 24(25)/2 × 10/100 × 1/12 = 5P/2

therefore, Amount deposited + 1 = Maturity amount

24 P + 5P/2 = 132500

therefore,

53P/2 = 132500

therefore,

₹5000

Glad help you,

it helps you,

thanks.