Question

HEY GUYS A LIL HELP HERE.

THE SUM OF FIRST "n" NATURAL NUMBER IS __________.
A)n
B)n2
C)n(n+1)
D)n(n+1)/2.


PLZ HELP ME.......

Answer 1

Hey Your answer is

we have

a= 1
c.d. = 1

ATQ,

$sn = n \div 2(2a + (n - 1)d)$

1/2(2×1+(1-1)1)

1/2(2)

1

So the answer is
A. n