Question

Hey guys can u solv this for me!!!❤plzz❤​

Answer 1

SOLUTION ☺️

Given equation= 4x-3y+1=0

Put the value of x &y

= 4(3k+2)-3(2k-1)+1=0

= 12k+8-6k+3+1=0

=6k+12=0

=6k= -12

=k= -12/6

=k= -2 answer.

Answer 2

x = 3k + 2 .....(1)

y = 2k - 1.......(2)

Equations (1) and (2) in 4x - 3y + 1 = 0,

4(3k + 2) - 3(2k - 1) +1 = 0

12k + 8 - 6k + 3 + 1 = 0

6k + 12 = 0

6k = -12

k = -12 ÷ 6

k = -2