Question

Factorise the following
a^8-b^8

Answer 1

Here is your answer. Hope I helped!

Answer 2

Factor a^8-b^8

a8−b8a8-b8

Rewrite a8a8 as (a4)2(a4)2.

(a4)2−b8(a4)2-b8

Rewrite b8b8 as (b4)2(b4)2.

(a4)2−(b4)2(a4)2-(b4)2

Since both terms are perfect squares, factor using the difference of squaresformula, a2−b2=(a+b)(a−b)a2-b2=(a+b)(a-b)where a=a4a=a4 and b=b4b=b4.

(a4+b4)(a4−b4)