Question

hey guys, can you all answer this question. the first one to answer i will matk you as brainliest ​

Answer 1

Answer:

badme bywi okkllllllllkkk

Answer 2

Answer:

k=0

Step-by-step explanation:

(k^2+4)x^2+13x+4k=0

A=k^2+4, b=13, c=4

Let the zeroes be x and 1/x as the zeroes are reciprocal to each other.

Product of zeroes=c/a

x×1/x=4/k^2+4

1=4/k^2+4

k^2+4=4

k^2=4-4

k^2=0

k=0

HOPE THIS BRING A SMILE IN YOUR FACE