Question

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Answer 1

Answer:

Explanation:

Initial speed of the truck, u = 0 (at rest)

Acceleration of the truck, a=5\ m/s^2

Time, t = 4 s

1. Let v is the final speed of the truck. Using the first equation of motion to find it as :

v=u+at

v=5\times 4

v = 20 m/s

2. Let s is the distance covered by the truck. It is given by :

s=ut+\dfrac{1}{2}at^2

s=\dfrac{1}{2}\times 5\times 4^2

s = 40 meters

Hence, this is the required solution.

Explanation:

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Answer 2

Answer:

Please refer to the attachment.

Explanation: