Question

Hey guys ,
Explain cernot cycle &derive the equation of efficiency...

Answer in long.... don't spam... plz
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Answer 1

Answer:

Hey Bobby❤️

Explanation:

here is your answer

The Cernot cycle can be thought as most effeciemt heat engine cycle allowed by physics laws.

In order to approach the Cernot effeciency the process involved in the heat engine cycle must be reversible and involve no chance to entrophy.

the Carnot cycle is the most efficient cycle of operating between two specific temperature limits but it is not a suitable model of power cycles .

Limitations of Carnot cycle

1.The working fluid at 3 is in both liquid and vapour state it is difficult to compress two phase mixture isentropically

2.practically it is not possible to neglet friction between piston and cylinder

derivation of the equation of efficiency

we know that

QH = RTh ln (v 2/ v1)

QL = RTl ln (v3/ v4)

the effeciency of Carnot cycle is

$nl \: 1 - \frac{ql}{qh} = \frac{1 - rt \: ln \: \frac{v3}{v4} }{rth \: ln \: \frac{v2}{v1} }$

process 1

$p1 \: {v1}^{ \gamma } = p4 {v4}^{ \gamma } = \: \frac{th}{tl} = { \binom{v4}{v1} }^{ \gamma - 1}$

process 2 and 3 we have

$p2 {v2}^{ \gamma } = p3 {v3}^{ \gamma } = \frac{th}{tl} = \frac{v3}{v2} \gamma$

$\frac{v4}{v1} = \frac{v3}{v2}$

$\frac{v2}{v1} = \frac{v3}{v2}$

$hl = 1 - \frac{tl}{th}$

the all of the entire engine is reversinle so we write

$h \: rec \: = \frac{1 - tl}{th}$

$thanku$

bobby