hey guys!good morning
plz solve my question
BOA is a diameter of a circle and the tangent at a point p meets ba produced at t. if angle PBO is equal to 30 degree then find angle PTA
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hello mate,
So, it is given that angle PBO = 30°
Therefore., in trianglePTB
angle PTB = 90° ( because radius drawn from the center of the circle is perpendicular to tangent)
therefore in PTB =
angle PTA + angle PTB + angle PBO = 180° ( angle sum property of triangle)
angle PTA + 90° + 30° = 180°
angle PTA = 180° - 120°
angle PTA = 60 °.
I hope this helps u.
So, it is given that angle PBO = 30°
Therefore., in trianglePTB
angle PTB = 90° ( because radius drawn from the center of the circle is perpendicular to tangent)
therefore in PTB =
angle PTA + angle PTB + angle PBO = 180° ( angle sum property of triangle)
angle PTA + 90° + 30° = 180°
angle PTA = 180° - 120°
angle PTA = 60 °.
I hope this helps u.
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⏩⏩Refer to the attachment above for your solution ⬆⬆
Hope it will helps you!
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