Question

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Prove 0 = 1

Answer 1

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Answer 2

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$\underline{To \: \: Prove}$ ➡ $\boxed{ 0 = 1 }$

$Let ,\\ \\ a \: = 1 \: \: \: \: \: \: and \: \: \: \: \: \: b = 1$

$So ,\: \: \: \\ \\ a = b \: \: \: \: - - - - > (1)$

$Now ,\\ \\ \underline{Multiplying \: \: \: both \: \: \: sides \: \: \: of \: \: eq.(1) \: \: by \: \: a} \\ \\ We \: \: get, \: \\ \\ \: \: \: \: a \times a = a \times b \\ \\ = > a {}^{2} = ab \: \: - - - - > (2)$

$\underline{Substracting \: \: \: b {}^{2} \: \: \: from \: \: both \: \: sides \: \: of \: \:eq. (2)} \\ \\ We \: \: get ,\\ \\ a {}^{2} - b {}^{2} = ab - b {}^{2} \\ \\ = > (a + b)( a- b) = b(a - b) \\ \\ = > a + b = b \\ \\ = > a + a = a \: \: \: \: [as \: \: \: a = b \: \: from \: (1)] \\ \\ = > 2 a= a \: \: \: \\ \\ = > 2 = 1 \\ \\ = > 2 - 1 = 1 - 1 \\ \\ = > 1 = 0 \\ \\ = > 0 = 1$

$\underline{Hence \: \: \: Proved. }$

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