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help me out with the given question.
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Sn = 2n^2 + 3n
=> n/2 [ 2a + (n-1)d] = n( 2n +3)
=> 2a +(n-1) d = 2(2n + 3)
=> 2a +(n-1) d = 4n + 6
=> 2a +(n-1) d = 10 + 4n - 4
=> 2a +(n-1) d = 10 +4(n-1)
On Comparing both sides, we get
2a = 10
=> a = 5
And , d = 4
T16 = a + 15d
= 5 + 15× 4
= 5 + 60
= 65
=> n/2 [ 2a + (n-1)d] = n( 2n +3)
=> 2a +(n-1) d = 2(2n + 3)
=> 2a +(n-1) d = 4n + 6
=> 2a +(n-1) d = 10 + 4n - 4
=> 2a +(n-1) d = 10 +4(n-1)
On Comparing both sides, we get
2a = 10
=> a = 5
And , d = 4
T16 = a + 15d
= 5 + 15× 4
= 5 + 60
= 65
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