Hey Guys
Help me with this:-
This:- If the p(th) term of an A.P. is 1/q and q(th) term is 1/p.
Prove that the sum of first pq term of an A.P. is ( pq+1/2).
C.B.S.E. Maths Class 10.
( WOULD BE HELPFUL IF YOU USE ALL THE STEPS.)
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Given pth term = 1/q
That is ap = a + (p - 1)d = 1/q
aq + (pq - q)d = 1 --- (1)
Similarly, we get ap + (pq - p)d = 1 --- (2)
From (1) and (2), we get
aq + (pq - q)d = ap + (pq - p)d
aq - ap = d[pq - p - pq + q]
a(q - p) = d(q - p)
Therefore, a = d
Equation (1) becomes,
dq + pqd - dq = 1
d = 1/pq
Hence a = 1/pq
Consider, Spq = (pq/2)[2a + (pq - 1)d]
= (pq/2)[2(1/pq) + (pq - 1)(1/pq)]
= (1/2)[2 + pq - 1]
= (1/2)[pq + 1]
That is ap = a + (p - 1)d = 1/q
aq + (pq - q)d = 1 --- (1)
Similarly, we get ap + (pq - p)d = 1 --- (2)
From (1) and (2), we get
aq + (pq - q)d = ap + (pq - p)d
aq - ap = d[pq - p - pq + q]
a(q - p) = d(q - p)
Therefore, a = d
Equation (1) becomes,
dq + pqd - dq = 1
d = 1/pq
Hence a = 1/pq
Consider, Spq = (pq/2)[2a + (pq - 1)d]
= (pq/2)[2(1/pq) + (pq - 1)(1/pq)]
= (1/2)[2 + pq - 1]
= (1/2)[pq + 1]
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hey MATE here is your answer..
the answer is from RD SHARMA
the answer is from RD SHARMA
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