hey guys .....
here is ur question but don't spam
ans . fast today is my exam
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Answers
1. (6+6/2,4+4/2) = (6,4)
2. Distance between Sita and Anita =√(6-3)²+(1-4)² = √9+9 = √18 = 3√2
3. Distance between Gita and Sita = √(6-3)²+(7-4)² = √9+9 = 3√2
Now, distance between Gita and Rita =
√(9-6)²+(4-7)² = √9+9 = 3√2
So, Sita and Rita are equidistant from Gita.
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Fóllòw MË ☺️☺️
Answer:
Sita, Gita, Rita and Anita are sitting at A(3,4), B(6,7), C(9,4), D(6,1) respectively.
(i)
Teacher tells Anjali to sit in the middle of the four students.
Middle of 4 students = Mid-point of BD and Midpoint of AC.
Thus, coordinates are,
==> (6 + 6/2, 7 + 1/2)
==> (6,4)
- Therefore, coordinates are (6,4).
(ii)
Distance between Sita and Anita.
Use the distance formula.
d = √(x₂ - x₁)² + (y₂ - y₁)
==> √(6 - 3)² + (1 - 4)²
==> 3√2
- Hence, distance is 3√2
(iii)
Gita = B(6,7)
The points Equidistant from B are A and C.
- Hence, Sita and Rita are equidistant from Gita.
#Hope my answers helped you