Hey guys hlp me with this qstn!!!
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Answer:
(a) a is a positive integer.
is the answer.
Step-by-step explanation:
Let a=p1.p2.p3.p4.p5.....pn where, p1, p2, p3, ..., pn are prime numbers, which are necessarily not distinct.
⇒a^2=(p1.p2.p3.p4.p5.....pn).(p1.p2.p3.p4.p5......pn)
It is given that p divides a^2.
From the Fundamental theorem of Arithmetic,
we know that every composite number can be expressed as product of unique prime numbers.
This means that p is one of the numbers from (p1.p2.p3.p4.p5......pn).
We have a=(p1.p2.p3.p4.p5..pn) and p is one of the numbers from (p1.p2.p3.p4.p5......pn).
It means that p also divides a.
Hence, it is proved that if p divides a^2 then it also divides a.
PrativaDewri:
thnkz
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