hey guys if u r intelligent, answer this;
Attachments:
JamesonEmpire:
hey anybody know question no.16
Answers
Answered by
1
ANSWER IS..........
now let as assume theta=β
then,
(1+cot²β)tanβ/sec²β
we know that 1+cot²β=cosec²β
cosec²β*tanβ/sec²β
cot²β*tanβ. [tanβ=1/cotβ]
cotβ = COT THETA
I HOPE THIS WILL HELP U
now let as assume theta=β
then,
(1+cot²β)tanβ/sec²β
we know that 1+cot²β=cosec²β
cosec²β*tanβ/sec²β
cot²β*tanβ. [tanβ=1/cotβ]
cotβ = COT THETA
I HOPE THIS WILL HELP U
your so thanks
your most welcome!
u r wlc
Answered by
1
Here is your answer in attachment
hope it help you
hope it help you
Attachments:
Similar questions