Math, asked by Alicia030, 10 months ago

Hey guys!❤️If you can answer this question with all the steps and working out, I'll mark your answer as the brainliest (and I'll love u 4ever)!!!​

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Answers

Answered by Anonymous
1

2, 5/2 ,3

Step-by-step explanation:

Given polynomial is 2x³-15x²+37x-30 =0

Zeros of polynomials are : a-b, a, a+b

Comparing the given polynomial with Ax³+Bx²+Cx+D=0

here A=2, B= -15 ,C=37 and D=  -30

As we know that Sum of zero's = - B/A 

a-b+a+a+b= - (-15)/2

3a= 15/2

a=5/2

Product of Zeros = -D/A

(a-b)a(a+b)= - (-30)/2

a[a²-b²]=15

Substituting the value of a in above equation, we get the value of b

[5/2][(5/2)²-b²]=15

25/4- b²=6

25-4b²=6x4

-4b²=24-25

-4b²=-1

b²=1/4

b= ±1/2

Zero's of polynomials are : a-b , a, a+b =5/2-1/2  , 5/2 , 5/2+1/2

=4/2 , 5/2, 6/2

=2, 5/2 ,3

Answered by Siddharta7
0

Answer:

5/2, 1/2

Step-by-step explanation:

Now, using the relation between zeroes and the coefficients of the given cubic polynomial, we have:

Sum of roots = a - b + a + a + b = 15/ 2

=> 3a = 15/2

=> a = 5/2

Also,

Product of roots = (a - b) * a * (a + b) = 15

=> a(a² - b²) = 15

=> (5/2) * (a² - d²) = 15

=> d² = 1/4

=> d = 1/2

Therefore,

Zeroes are 5/2, 1/2

Hope it helps!

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