Question

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Answer 1

hey

here is your answer

The sides of the triangle are 122 m, 22 m and 120 m.

Perimeter of the triangle is 122 + 22 + 120 = 264m

Semi perimeter of triangle (s) = 264/2 = 132 m

Using heron’s formula,

Area of the advertisement = √s (s-a) (s-b) (s-c)

= √132(132 – 122) (132 – 22) (132 – 120) m2

= √132 × 10 × 110 × 12 m2

= 1320 m2

Rent of advertising per year = ₹ 5000 per m2

Rent of one wall for 3 months = ₹ (1320 × 5000 × 3)/12 = ₹ 165000

hope its help you

thanxx and be brainly.................................................................

Answer 2

In Order to Find the Rent the Company paid, First we need to Find the Area of Triangular Side Wall

We know that : Area of Triangle is given by :  $\frac{1}{2} \times Base \times Height$

Given : The Base of the Triangle = 120 m

Given : The Height of the Triangle = 22 m

⇒ Area of the Triangular Wall :  $\frac{1}{2} \times 22 \times 120 = (22 \times 60) = 1320\;m^2$

Given : The Rent for 12 Months is 5000 per m²

⇒ The Rent for 3 Months is :  $\frac{5000}{4} = 1250\;per\;m^2$

⇒ The Rent for 3 Months for One m² Area = ₹ 1250

But, The Triangular Wall Area is 1320 m²

The Rent for 3 Months for 1320 m² Area = 1320 × 1250 = ₹ 1650000