Question

Hey Guys


Please solve all the questions in the Above file ☝☝☝☝.

thank u

Answer 1

$\begin{tabular}{|c|c|c|}\cline{1-3} \sf Multiple & \sf Prefix & \sf Symbol\\\cline{1-3}\sf 10^{-21}&\sf zepto & \sf z\\ \cline{1-3} \sf 10^{-18}&\sf atto & \sf a\\ \cline{1-3} \sf 10^{-15}&\sf femto & \sf f\\ \cline{1-3} \sf 10^{-12}&\sf pico & \sf p\\ \cline{1-3} \sf 10^{-9}&\sf nano & \sf n\\ \cline{1-3} \sf 10^{-6}&\sf micro & \sf \mu\\ \cline{1-3}\sf 10^{-3}&\sf milli & \sf m\\ \cline{1-3}\sf 10^{-2}&\sf centi & \sf c\\ \cline{1-3} \sf 10^{-1}&\sf deci & \sf d\\ \cline{1-3}\end{tabular}$

$\begin{tabular}{|c|c|c|}\cline{1-3} \sf Multiple & \sf Prefix & \sf Symbol\\\cline{1-3}\sf 10^{1}&\sf deca & \sf da\\ \cline{1-3} \sf 10^{2}&\sf hecto & \sf h\\ \cline{1-3} \sf 10^{3}&\sf kilo & \sf k\\ \cline{1-3} \sf 10^{6}&\sf mega & \sf M\\ \cline{1-3} \sf 10^{9}&\sf giga & \sf G\\ \cline{1-3} \sf 10^{12}&\sf tera & \sf T\\ \cline{1-3}\sf 10^{15}&\sf peta & \sf P\\ \cline{1-3}\sf 10^{18}&\sf exa & \sf E\\ \cline{1-3} \cline{1-3}\sf 10^{21}&\sf zeta & \sf Z\\ \cline{1-3}\end{tabular}$

$\textsf{1.1 (i) \;Given : 40\;Em}$

$\textsf{From the Table, We can notice that : E is the symbol of Prefix \boxed{\textsf{exa}}}$

$\bigstar\;\;\mathsf{exa\;represents\;Multiple\;10^{18}}$

$\implies \mathsf{40\;Em = 40 \times 10^{18}\;m}$

$\implies \mathsf{40\;Em = 4 \times 10^{19}\;m}$

$\textsf{1.1 (ii) \;Given : 1\;fg}$

$\textsf{From the Table, We can notice that : f is the symbol of Prefix \boxed{\textsf{femto}}}$

$\bigstar\;\;\mathsf{femto\;represents\;Multiple\;10^{-15}}$

$\implies \mathsf{1\;fg = 1 \times 10^{-15}\;g}$

$\mathsf{We\;know\;that\; : 1\;gram = 10^{-3}\;kilogram}$

$\implies \mathsf{1\;fg = 10^{-15}\;\times 10^{-3}\;kg}$

$\implies \mathsf{1\;fg = 10^{-18}\;kg}$

$\mathsf{1.1 (iii)\;\;Given : 10.12\; \mu s}$

$\mathsf{We\;know\;that :Base\;unit\;of\;\mu s\;is\;second}$

$\textsf{From the Table, We can notice that : \mu is the symbol of Prefix \boxed{\textsf{micro}}}$

$\bigstar\;\;\mathsf{micro\;represents\;Multiple\;10^{-6}}$

$\implies \mathsf{10.12\;\mu s = (10.12 \times 10^{-6}\;s) = 1.012 \times 10^{-5}\;s}$

$\textsf{1.1(iv)\;\;Given : 90\;miles/hr}$

$\bigstar\;\;\textsf{We know that : \boxed{\textsf{1 Mile = 1609.34\;metre}}}$

$\bigstar\;\;\textsf{We know that : \boxed{\textsf{1 Hour = 3600\;sec}}}$

$\implies \mathsf{90\;miles/hr = \bigg(90 \times \dfrac{1690.34}{3600}\bigg)\;m/s}$

$\implies \mathsf{90\;miles/hr = \bigg(\dfrac{1690.34}{40}\bigg)\;m/s}$

$\implies \mathsf{90\;miles/hr = 42.258\;m/s}$

$\mathsf{1.2\;\;Given : The\;Density\;of\;the\;Metal\;is\;7.56\;g\;cm^{-3}}$

$\mathsf{We\;know\;that\; : 1\;gram = 10^{-3}\;kilogram}$

$\mathsf{We\;know\;that\; : 1\;cm = 10^{-2}\;m}$

$\mathsf{\implies 7.56\;g\;cm^{-3} = 7.56 \times (10^{-3}\;kg) \times (10^{-2}\;m)^{-3}}$

$\mathsf{\implies 7.56\;g\;cm^{-3} = 7.56 \times (10^{-3}\;kg) \times (10^{6}\;m^{-3})}$

$\mathsf{\implies 7.56\;g\;cm^{-3} = 7.56 \times (10^{-3} \times 10^{6})\;kg\;m^{-3}}$

$\mathsf{\implies 7.56\;g\;cm^{-3} = 7.56 \times 10^{3}\;kg\;m^{-3}}$

$\mathsf{\implies 7.56\;g\;cm^{-3} = 7560\;kg\;m^{-3}}$

Answer 2

1.1 (i) Given : 40Em

★exarepresents Multiple 10

18

⟹40Em=40×10

18 m

⟹40Em=4×10

19 m

Given : 1fg

\bigstar\;\;\mathsf{femto\;represents\;Multiple\;10^{-15}}★femtorepresentsMultiple10

−15

\implies \mathsf{1\;fg = 1 \times 10^{-15}\;g}⟹1fg=1×10

−15

g

\mathsf{We\;know\;that\; : 1\;gram = 10^{-3}\;kilogram}Weknowthat:1gram=10

−3

kilogram

\implies \mathsf{1\;fg = 10^{-15}\;\times 10^{-3}\;kg}⟹1fg=10

−15

×10

−3

kg

\implies \mathsf{1\;fg = 10^{-18}\;kg}⟹1fg=10

−18

kg

\mathsf{1.1 (iii)\;\;Given : 10.12\; \mu s}1.1(iii)Given:10.12μs

\mathsf{We\;know\;that :Base\;unit\;of\;\mu s\;is\;second}Weknowthat:Baseunitofμsissecond

\bigstar\;\;\mathsf{micro\;represents\;Multiple\;10^{-6}}★microrepresentsMultiple10

−6

\implies \mathsf{10.12\;\mu s = (10.12 \times 10^{-6}\;s) = 1.012 \times 10^{-5}\;s}⟹10.12μs=(10.12×10

−6

s)=1.012×10

−5

s

\textsf{1.1(iv)\;\;Given : 90\;miles/hr}1.1(iv)Given : 90miles/hr

\implies \mathsf{90\;miles/hr = \bigg(90 \times \dfrac{1690.34}{3600}\bigg)\;m/s}⟹90miles/hr=(90×

3600

1690.34

)m/s

\implies \mathsf{90\;miles/hr = \bigg(\dfrac{1690.34}{40}\bigg)\;m/s}⟹90miles/hr=(

40

1690.34

)m/s

\implies \mathsf{90\;miles/hr = 42.258\;m/s}⟹90miles/hr=42.258m/s

\mathsf{1.2\;\;Given : The\;Density\;of\;the\;Metal\;is\;7.56\;g\;cm^{-3}}1.2Given:TheDensityoftheMetalis7.56gcm

−3

\mathsf{We\;know\;that\; : 1\;gram = 10^{-3}\;kilogram}Weknowthat:1gram=10

−3

kilogram

\mathsf{We\;know\;that\; : 1\;cm = 10^{-2}\;m}Weknowthat:1cm=10

−2

m

\mathsf{\implies 7.56\;g\;cm^{-3} = 7.56 \times (10^{-3}\;kg) \times (10^{-2}\;m)^{-3}}⟹7.56gcm

−3

=7.56×(10

−3

kg)×(10

−2

m)

−3

\mathsf{\implies 7.56\;g\;cm^{-3} = 7.56 \times (10^{-3}\;kg) \times (10^{6}\;m^{-3})}⟹7.56gcm

−3

=7.56×(10

−3

kg)×(10

6

m

−3

)

\mathsf{\implies 7.56\;g\;cm^{-3} = 7.56 \times (10^{-3} \times 10^{6})\;kg\;m^{-3}}⟹7.56gcm

−3

=7.56×(10

−3

×10

6

)kgm

−3

\mathsf{\implies 7.56\;g\;cm^{-3} = 7.56 \times 10^{3}\;kg\;m^{-3}}⟹7.56gcm

−3

=7.56×10

3

kgm

−3

\mathsf{\implies 7.56\;g\;cm^{-3} = 7560\;kg\;m^{-3}}⟹7.56gcm

−3

=7560kgm

−3