Question

♦Hey guys Plz!Answer This!♦

(sec A + Tan A) (1-sin A)=?



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Answer 1

Answer:

seca(1-sina)(1/cosa+Sina/cosa)

=> seca(1-sina)(1-sina)/cosa

=> seca(1-sin²a)/cosa

=> seca cos ²a/cosa

=> 1/cos a×cosa

=1

Answer 2

Answer:

(sec A+tan A)(1-sinA)

=(1/cos A + sin A/cos A)(1-sinA)

=[(1+sinA)/cosA](1-sinA)

=(1+sinA)(1-sinA)/cosA

=(1-sin^2 A)/cosA

=(cos^2 A)/cos A

=cos A

hope it help uh

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