Question

hey guys plz help me solve 19 ques.
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Answer 1

angle AEB = 90° ( angle formed by the diameter)

Now in ∆AEB
angle AEB + angle EAB + angle EBA = 180° ( sum of all angles of a traingle is 180°)

90° + 65° + angle EBA = 180°
angle EBA = 25°

since ED || AB and EB is transversal , then

angle BED = angle EBA ( Alternate interior angle)

angle BED = 25°

now EBCD is a cyclic quadrilateral coz all four vertices of the quad. is on the circle)

so,
angle BED + angle BCD = 180° ( sum of opposite angles of a cyclic quad. is 180° )

25° + angle BCD = 180°
angle BCD = 180-25 = 155°