Physics, asked by Shreyansh900, 6 months ago

HEY GUYS !!! PLZ HELP ME WITH THE PHYSICS PROBLEM OF OBJECTIVE - II OF H.C.VERMA

THE CORRECT OPTIONS ARE
OPTION C AND OPTION D

I JUST WANTED TO KNOW THAT IF THIS EQUATION IS IN THE FORM OF

x = ut \:  + 0.5a{t}^{2}
AND BY COMPARING THE EQUATION WITH THE ABOVE ONE WE CAN GET

INITIAL VELOCITY = u
ACCELERATION =2a

AND PUTTING t=2s IN THE EQUATION WE GET x=0

SO WHY ONLY OPTIONS C AND D ARE CORRECT AS THERE'S A OPTION A WHERE THE INITIAL VELOCITY IS GIVEN 'u' m/s

SO ACCORDING TO ME OPTION A SHOULD BE ALSO CORRECT...

PLZ EXPLAIN ME GUYS...THE BEST EXPLANATION WITHIN 120 MINUTES WILL GET A BRAINLIST I PROMISE


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Answers

Answered by muzammil5497
1

Answer:

the correct options are a,c and d

Explanation:

since by substituting t=2s in equation we get X=0 which is true

and we know that displacement formula is s=ut+1/2at^2

therefore we can write the given equation as X=u(t-2s)+1/2(2a)(t-2s)^2

where u is initial velocity and time =t-2s

and acceleration=2a

therefore a and c options are correct

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