Question

hey guys plz solve..

√3x² - 2√2x - 2√3 = 0

plz as quick as possible

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Answer 1

√3x²-2√2x-2√3
√3x²-(3√2-√2)x-2√3 = 0
√3x²-3√2x+√2x-2√3 = 0
√3x²-√3×√3×√2x+√2x-√2×√2×√3 = 0
√3x (x-√6) +√2 ( x-√6) = 0
(x-√6) (√3x+√2) = 0

(x-√6) = 0
X = √6 Ans

(√3x+√2) = 0
√3x = -√2
X = -√2/√3 Ans

Answer 2

հҽվ ժҽɑɾҽՏԵ !!

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$\sqrt{3}{x}^{2} - 2\sqrt{2}x - 2\sqrt{3} = 0\\ \\ Splitting \:middle \:term \\ \\ \sqrt{3}{x}^{2} - 3\sqrt{2}x + 1\sqrt{2}x - 2\sqrt{3} = 0 \\ \\ Taking \: commons \\ \\ \sqrt{3}x(x - \sqrt{6}) + \sqrt{2}( x-\sqrt{6}) = 0 \\ \\( \sqrt{3} x+ \sqrt{2} ) ( x - \sqrt{6} ) = 0\\ \\ \sqrt{3}x = -\sqrt{2} = 0 , x-\sqrt{6} = 0\\ \\ x = \frac{{-\sqrt{2}}}{{\sqrt{3}}}, x= +\sqrt{6}$

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