Question

HEY GUYS

PLZ SOLVE THIS QUESTION URGENT​

Answer 1

Answer:

Hey Buddy,

We know, The horizontal component(BH) of the electric field is given by,

BH= Be cos(θ)

Here θ is the angle of dip at the given place and Be is the net magnetic field.

At θ= 60°,

BH = Be Cos(60°) = Be x (1/2)

Be = 2BH = 2B (since BH = B)

Now horizontal component at equator be,

BH = Be Cos(θ)

Since we have angle of dip at equator =0

BH=Be cos(0) = Be = 2B

BH = 2B.

Hope That Helps...