hey guys plzz help me to solve this ques.
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(-2)³+a(-2)+b=0,
-8-2a+b=0,
then
-2a+b=8,........eq(1),
(-3)³+a(-3)+b=0,
-27-3a+b=0,
then
-3a+b=27,............eq(2),
subtract eq(1) from eq(2), we get
-a=27-8,
-a=19,
then
a=-19,
put this value in eq(1), we get
-2(-19)+b=8,
38+b=8,
then
b=8-38,
b=-30
-8-2a+b=0,
then
-2a+b=8,........eq(1),
(-3)³+a(-3)+b=0,
-27-3a+b=0,
then
-3a+b=27,............eq(2),
subtract eq(1) from eq(2), we get
-a=27-8,
-a=19,
then
a=-19,
put this value in eq(1), we get
-2(-19)+b=8,
38+b=8,
then
b=8-38,
b=-30
Answered by
1
hey there➡️
here ur answer which i wrote and attached for u❗
hope this helps u✅✔️✅✔️
be brainly❤️
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