Question

HEY GUYS⭐⭐
PLZZZ HELP IN MY Q'S
CLASS 11
ITS VERY URGENT
I'LL MARK AS BRAINLIEST ☺️☺️NO SPAMMING ⭕⭕
EXPLAIN PROPERLY⏩⏩

Answer 1

Hey friend, Harish here.

Here is your answer.

2.

We know that mass = density × volume

Let density of the cone be ρ . Then,

$\mathrm{m_{conc}= \rho \times \frac{1}{3} \pi \ \big(2R\big)^3 \times 4R = \frac{16}{3}\pi(R)^3 \rho }$

The centre of mass will be at a height of O which equals to h/4 = R .

$\mathrm{ m_{(sphere)} = (12\rho) \times \frac{4}{3} \pi \ \big(R\big)^3 = {16}\pi(R)^3 \rho }} = \mathrm{ 3 \times m_{(conc)} }$

This centre of mass is at a distance of => 4R + R = 5R .

Then, Centre of mass of whole system is ;

$\mathrm{C.O.M = \frac{mR+3m(5R)}{m+3m}=\frac{16mR}{4m}= 4R}$

Therefore the C.O.M is at as distance of 4R from O.

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