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Let us assume a wheel as shown in figure, and 24rod spokes in it.
Find the moment of inertia of wheel,
Mass of wheel = 24M
Radius of wheel = L
We know that, a wheel having mass of m and radius r , has inertia equal to mr²
Hence,
Moment of inertia of wheel = mass of wheel ×( radius)²
= 24M × (L)²
= 24ML²
Find the moment of inertia of rods,
First we need to find mass of inertia of one rod,
mass of one = M
lenght of one rod = L
Inertia of one rod = 1/3×ML²
Inertia of 24 rods = 24 × ML²/3
= 8ML²
Moment of inertia of Whole wheel = 24ML² + 8ML² = 32ML²
Find the moment of inertia of wheel,
Mass of wheel = 24M
Radius of wheel = L
We know that, a wheel having mass of m and radius r , has inertia equal to mr²
Hence,
Moment of inertia of wheel = mass of wheel ×( radius)²
= 24M × (L)²
= 24ML²
Find the moment of inertia of rods,
First we need to find mass of inertia of one rod,
mass of one = M
lenght of one rod = L
Inertia of one rod = 1/3×ML²
Inertia of 24 rods = 24 × ML²/3
= 8ML²
Moment of inertia of Whole wheel = 24ML² + 8ML² = 32ML²
Shubhendu8898:
There are two possible solution
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