One third of a certain journey was covered at a rate of 25 km per hour, one fourth at rate of 30 km per hour and the rest of 50 km per hour. the average speed
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Let distance be 120 KM, hence 30 KM is covered by @ 25 kmph and 40 km covered by @ 30 kmph and rest 50 km has been covered@ 50 km.
Now, average velocity= (120/total time taken);
= {120/[(30/25)+(40/30)+(50/50)}]
= 3600/106 = 1800/53 km/h.
Now, average velocity= (120/total time taken);
= {120/[(30/25)+(40/30)+(50/50)}]
= 3600/106 = 1800/53 km/h.
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