Question

HEY GUYS⭐⭐
PLZZZ HELP IN MY QS
CLASS 11
ITS VERY URGENT
I'LL MARK AS BRAINLIEST ☺️☺️NO SPAMMING ⭕⭕
EXPLAIN PROPERLY⏩⏩

Answer 1

i hope this is helpful to you...

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Answer 2

At first we will find the equation of the line.

The slope of the line ....

m = (y2 - y1)/(x2 - x1)

m = (16-0)/(0-8)

m=-2.

The equation by the formula y-y1 = m(x-x1)

y - 0 = -2(x-8)

y= -2x + 16

2x +y-16=0

ans. 1

Now , using the formula for finding distance of a point from line.....$d = abs. val. \frac{ax_{1} + by_1 +c}\sqrt{{x_1^{2} +y_{1}^{2}}}$

$d = \frac{2(2) + 1(2) -16}{\sqrt{2^{2}+ 1^{2}}} =\frac{-10}{\sqrt{5}} =-2\sqrt{5} =-\sqrt{20}$

absolute value of -√20 = √20.

ans 2.

If PDOC is a square , then PD = PC or x co- ordinate of point p = y co-ordinate.

let the length of side of square is a .

then x co-ordinate =a & y co - ordinate = a

so p(a,a).

Point p is on the line 2x +y-16=0 , so it will satisfy the equation.

so....

2a +a-16=0

3a=16

a=16/3.

so the sum of x co -ordinate of point p =a+a=2a

2a= 2(16/3)=32/3.

Let The possible ordered pair is (a,b). The possible values of x and y will be the number of possible ordered pairs.

The area is 30 sq.

so the multiplication of rectangle = 30sq

ab=30sq......................(1)

This point (p) lies on the line 2x+y-16=0 .

so it will satisfy the equation.

so .......

2a+b-16=0

or b=16-2a

If we put this value of b in the first equation.....

a(16-2a)=0

16a -2a^2=0

2a^2 -16a=0

This is a quadratic equation of a.

here D = (256-0)= +ve

so the equation will have two real and unique solutions.

so there are two points for which the area will be 30sq.

these points can also be calculated by solving the quadratic equation.