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Explanation:
16. we know that, force = mass *acceleration ...(1)
f=5......m=20kg
put the value of m and f in eqn 1
5/20 =a
1/4 = a
a= 0.25
17. v²-u² =2as
given, v=20 u =0 s=50
20×20= 2×a×50
400/100 = a
a =4
18. F=m* a
a =5
so we assume that initially the object is at rest
u=0
v=at
t= v/a
t= 100/5
t =20s
19.Mass of the boy, m1 = 50 kg
Speed of boy, u1 = 5 m/s
Mass of trolley m2 = 20 kg
Speed of trolley u2 =1.5 m/s
Combined mass of boy and trolley, m = 20+ 50 = 70 kg law of conservation of momentum
m1 u1 + m2 u2 = mv 50 x 5 + 20 x 1.5 = 70 x v
v= 280/7 = 4
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2
Answer:
16 (b)
17(d)
20(c) ok correct answer
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