Hey Guys☺☺........[50 points]. ....
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IshmeetLotey:
hlo
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Answered by
9
Dimensions pf bigger box = 25cm x20cmx5cm
Tsa of bigger box = 2(lb+bh+hl)
=2(25x20+20x5+5x25)
=1450cm2
Dimension of smaller box =15cmx12cmx5cm
Tsa pf smaller box = 2(lb+bh+hl)
=2(15x12+12x5+5x15)
=630cm2
Tsa of 250 boxes of each type
=250(1450+630)
=250x2080
=520000cm2
Extra area required =5/100(1450+630)250
=26000cm2
Total cardboard required =520000+26000
=546000cm2
Total cost of cardboard sheet=546000x4/1000
=2184rs
Tsa of bigger box = 2(lb+bh+hl)
=2(25x20+20x5+5x25)
=1450cm2
Dimension of smaller box =15cmx12cmx5cm
Tsa pf smaller box = 2(lb+bh+hl)
=2(15x12+12x5+5x15)
=630cm2
Tsa of 250 boxes of each type
=250(1450+630)
=250x2080
=520000cm2
Extra area required =5/100(1450+630)250
=26000cm2
Total cardboard required =520000+26000
=546000cm2
Total cost of cardboard sheet=546000x4/1000
=2184rs
Answered by
4
HEY MATE!
Answer :
For bigger boxes :
t = 25 cm, b = 20 cm, h = 5 cm
Total surface area of 1 bigger box = 2(lb + bh + hl)
= 2(25 × 20 + 20 × 5 + 5 × 25) cm2
= 2 (500 + 100 + 125) cm2 = 1450 cm2
Area of cardboard required for overlaps
= 5% of 1450 cm2 = 1450x 5 /100 × cm2 = 72.5 cm2.
Total area of cardboard needed for 1 bigger box
= (1450 + 72.5) cm2 = 1522.5 cm2
Total area of cardboard needed for 250 bigger boxes = 1522.5 × 250 cm2
= 380625 cm2.
For smaller boxes :
t = 15 cm, b = 12 cm, h = 5 cm
Total surface area of 1 smaller box = 2 (lb + bh + hl)
= 2(15 × 12 + 12 × 5 + 5 × 15) cm2
= 2 (180 + 60 + 75) cm2 = 630 cm2
Area of cardboard required for overlaps
= 5% of 630 cm2 = 630x 5 /100 × cm2 = 31.5 cm2
Total area of cardboard needed for 1 smaller box = (630 + 31.5) cm2
= 661.5 cm2
Total area of cardboard needed for 250 smaller boxes
= 661.5 × 250 cm2 = 165375 cm2
Now, total area of cardboard needed for 500 boxes (250 bigger and 250
smaller boxes) = (380625 + 165375) cm2 = 546000 cm2
Cost of 1000 cm2 of cardboard = Rs 4
∴ Cost of 546000 cm2 of cardboard = Rs 4/1000 × 546000 = Rs 2184 Ans
Answer :
For bigger boxes :
t = 25 cm, b = 20 cm, h = 5 cm
Total surface area of 1 bigger box = 2(lb + bh + hl)
= 2(25 × 20 + 20 × 5 + 5 × 25) cm2
= 2 (500 + 100 + 125) cm2 = 1450 cm2
Area of cardboard required for overlaps
= 5% of 1450 cm2 = 1450x 5 /100 × cm2 = 72.5 cm2.
Total area of cardboard needed for 1 bigger box
= (1450 + 72.5) cm2 = 1522.5 cm2
Total area of cardboard needed for 250 bigger boxes = 1522.5 × 250 cm2
= 380625 cm2.
For smaller boxes :
t = 15 cm, b = 12 cm, h = 5 cm
Total surface area of 1 smaller box = 2 (lb + bh + hl)
= 2(15 × 12 + 12 × 5 + 5 × 15) cm2
= 2 (180 + 60 + 75) cm2 = 630 cm2
Area of cardboard required for overlaps
= 5% of 630 cm2 = 630x 5 /100 × cm2 = 31.5 cm2
Total area of cardboard needed for 1 smaller box = (630 + 31.5) cm2
= 661.5 cm2
Total area of cardboard needed for 250 smaller boxes
= 661.5 × 250 cm2 = 165375 cm2
Now, total area of cardboard needed for 500 boxes (250 bigger and 250
smaller boxes) = (380625 + 165375) cm2 = 546000 cm2
Cost of 1000 cm2 of cardboard = Rs 4
∴ Cost of 546000 cm2 of cardboard = Rs 4/1000 × 546000 = Rs 2184 Ans
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