Question

❤ Hey guys❤

The equation y= 4sinπ[ 200t-(x/25)] represents a transverse wave that travels in a stretched wire,where X and Y are in centimetre and t in seconds Find its wavelength and velocity are​

Answer 1

$y = 4 \sin\pi(200t - \frac{x}{25} ) \\ \\ normal \: form \: of \: a \: wave \: is \\ \\ y = a \sin(wt - kx) \\ \\ a = 4 \\ \\ w = 200\pi \\ \\ k = \frac{\pi}{25} \\ \\ λ = \frac{2\pi}{k} \\ \\ λ = \frac{2\pi}{ \frac{\pi}{25} } \\ \\ λ = 50cm \\ \\ v = \frac{w}{k} = fλ \\ \\ v = \frac{200\pi}{ \frac{\pi}{25} } \\ \\ v = 5000cm {sec}^{ - 1} \\ \\ also \\ \\ v = fλ \\ \\ f = \frac{v}{λ} \\ \\ f = 100 \: hertz \: or \: {sec}^{ - 1}$

hope it helps

Answer 2

Answer:0.5m,50ms-1

Explanation: