please solve this by quadratic equation
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100x^2-20x+1=0
100x^2-10x-10x+1=0
10x(10x-1)-1(10x-1)=0
(10x-1)(10x-1)=0
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[tex]100 {x}^{2} - 20x + 1 = 0 \\ we \: know \: that \: the \: quadru ic \: equation \\ a {x}^{2} + bx + c = 0 \\ \\ here \\ \: a : is \: compaired \: with \: = 100 \\ b : \: is \: compaired \: = - 20 \\ and \: c : is \: compaired \: = 1 \\ the \: quadric \: formula \: is \\ \\ x = \frac{ - b \frac{ + }{} \sqrt{ {b}^{2} - 4ac } }{2a} \\ = > x = \frac{ - ( - 20) \frac{ + }{} \sqrt{ {( - 20)}^{2} - 4.100.1 } }{2 \times 100} \\ = > x = \frac{20 \frac{ + }{} \sqrt{400 - 400} }{200} \\ = > x = \frac{20 \frac{ + }{} \sqrt{0} }{200} \\ then \\
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[tex]100 {x}^{2} - 20x + 1 = 0 \\ we \: know \: that \: the \: quadru ic \: equation \\ a {x}^{2} + bx + c = 0 \\ \\ here \\ \: a : is \: compaired \: with \: = 100 \\ b : \: is \: compaired \: = - 20 \\ and \: c : is \: compaired \: = 1 \\ the \: quadric \: formula \: is \\ \\ x = \frac{ - b \frac{ + }{} \sqrt{ {b}^{2} - 4ac } }{2a} \\ = > x = \frac{ - ( - 20) \frac{ + }{} \sqrt{ {( - 20)}^{2} - 4.100.1 } }{2 \times 100} \\ = > x = \frac{20 \frac{ + }{} \sqrt{400 - 400} }{200} \\ = > x = \frac{20 \frac{ + }{} \sqrt{0} }{200} \\ then \\
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✨✨hope.it helps✨✨
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