hey guys,
the sum of the digits in a two-digits number is 10. if 18 is subtracted from the number the result is the number eith the digits reversed. find the digit?
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2
Hey
Here is your answer,
The two digit number = 10x+y
x+y=10
10x+y-18=10y+x
10x - x + y -10y =18
9x -9y =18
Dividing by 9,
x - y =2
Solving both the equation,
X + y =10
X - y =2
_______
2x. =12
X=12/2
X=6
Substitute the value of x in equation to find the value of y,
X+y=10
Y=10-6
Y=4
Two digit number = 10x+y
=10x6+4
=60+4
=64
Hope it helps you!
Here is your answer,
The two digit number = 10x+y
x+y=10
10x+y-18=10y+x
10x - x + y -10y =18
9x -9y =18
Dividing by 9,
x - y =2
Solving both the equation,
X + y =10
X - y =2
_______
2x. =12
X=12/2
X=6
Substitute the value of x in equation to find the value of y,
X+y=10
Y=10-6
Y=4
Two digit number = 10x+y
=10x6+4
=60+4
=64
Hope it helps you!
Answered by
4
I hope this helps you!
@vaibhav246
@vaibhav246
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